Which trigger the internal error?

Question

Edit the content of mytest.sh.

#!/bin/bash    
ARGS=`getopt -o c`
eval set -- "${ARGS}"

while true;
do
    case "$1" in
        -c)
            echo "i am c"
            ;;
        *)
            echo "Internal error!"
            exit 1
            ;;
    esac
done

bash mytest.sh -c get the error info Internal error! ,why can't trigger the info i am c?

Have you tried `echo "$1"` to see what's in $1? (And then perhaps `echo "$2"` and so on...) — JJJ, Jun 17 '18 at 09:28
This might help: [How to debug a bash script?](http://unix.stackexchange.com/q/155551/74329) — Cyrus, Jun 17 '18 at 09:59
See: [An example of how to use getopts in bash](https://stackoverflow.com/q/16483119/3776858) — Cyrus, Jun 17 '18 at 10:56
May be you are using different implementation of getopt. I know that at-least there are BSD version and GNU version. — apatniv, Jun 17 '18 at 16:24

score 1 · Answer 1 · answered Jun 17 '18 at 16:39

#!/bin/bash    
ARGS=$(getopt -o c -- "$@")
eval set -- "${ARGS}"

while true;
do
    case "$1" in
        -c)
            echo "i am c"
            ;;
        *)
            echo "Internal error!"
            exit 1
            ;;
    esac
done

I really don't know what you intend to do. But the current code you have results in an infinite loop. Better thing would be: break from the while condition after the option is encountered.

Mostly likely a better thing to do:

#!/bin/bash    
ARGS=$(getopt -o c -- "$@")
eval set -- "${ARGS}"

while true;
do
    case "$1" in
        -c)
            echo "i am c"
            # do some processing.
            break
            ;;
        *)
            echo "Internal error!"
            exit 1
            ;;
    esac
done

Note: btw, prefer to use getopts instead of getopt

Which trigger the internal error?

1 Answers1