indexOf incorrectly says that an integer isn't in an array

Asked Jun 17 '18 at 16:53

Active Jun 17 '18 at 16:53

Viewed 30 times

I tried to get the index of the smallest integer in an array with the following code, but indexOf returns -1.

package tutorial;

import java.util.Arrays;


public class Lists {

public static void main(String[] args){

    int[] stuff = {4,3,2,1,8,4};
    int minValue = Arrays.stream(stuff).min().getAsInt(); 
    System.out.println(minValue);
    int smallestIndex = Arrays.asList(stuff).indexOf(minValue);
    System.out.println(smallestIndex);
}

}

asked Jun 17 '18 at 16:53

Damian Siniakowicz

Your problem is that your code is mixing up int primitive values and Integer objects. – GhostCat Jun 17 '18 at 16:56
In particular, `Arrays.asList(stuff)` is giving you a `List – k_ssb Jun 17 '18 at 16:58
So what is indexOf good for? And how can I get the index of the smallest number in the array without writing out a for loop? – Damian Siniakowicz Jun 17 '18 at 17:13
The only way is to write a for loop. `indexOf` works if you already have a `List` but doesn't work so well if you try to convert primitive arrays to lists (since lists can't contain primitive types). – k_ssb Jun 18 '18 at 09:41
thank you very much – Damian Siniakowicz Jun 19 '18 at 15:30

indexOf incorrectly says that an integer isn't in an array

0 Answers0