PHP: Passing array by reference fail

Question

I've the following code function:

function foo(&$vett) {

    $vettore = $vett;

    $vettore[] = "ciao";

    var_dump($vettore);
}

$v = array();

foo($v);

var_dump($v);

When I dump the final array is empty. Have you any idea of what could be?

So if you pass something by reference - __what's the point__ of assigning passed value to another one? — u_mulder, Jun 21 '18 at 07:05
https://stackoverflow.com/questions/2030906/are-arrays-in-php-passed-by-value-or-by-reference may be useful — Nigel Ren, Jun 21 '18 at 07:17
When you fixed it, you can post your own answer and accept it. Beside the reputation, your solution may be of some help for other users. — PJProudhon, Jun 21 '18 at 07:23

score 1 · Accepted Answer · answered Jun 21 '18 at 07:08

Because $v never modified. Inside the function you assign the variable into another variable. So nothing ever happen to the old $vett

try something like:

function foo(&$vett) {
    $vett[] = "ciao";
    echo __LINE__;
    var_dump($vett);
}

$v = array();
foo($v);
var_dump($v);

score 0 · Answer 2 · answered Jun 21 '18 at 07:07

0

Correct version is:

function foo(&$vett) {
    $vett[] = "ciao";
}

$v = array();
foo($v);
var_dump($v);

answered Jun 21 '18 at 07:07

u_mulder

2 Answers2