Let's say I have an array with the following values -
var arr = [true, true, false, false, false, true, false];
I'm looking for logic which will give me the following output -
[0,1,5]
Let's say I have an array with the following values -
var arr = [true, true, false, false, false, true, false];
I'm looking for logic which will give me the following output -
[0,1,5]
 
    
    You can use .reduce() to do this in one pass:
const arr = [true, true, false, false, false, true, false]
const indices = arr.reduce(
  (out, bool, index) => bool ? out.concat(index) : out, 
  []
)
console.log(indices)You start by passing an empty array [] as the initialValue to .reduce() and use a ternary ? operator to determine whether to .concat() the index or not.
Alternatively, you can use the more recent .flatMap() method:
const arr = [true, true, false, false, false, true, false]
const indices = arr.flatMap((bool, index) => bool ? index : [])
console.log(indices)If your browser does not yet support it, you'll get an Uncaught TypeError: arr.flatMap is not a function. In that case, you can use my polyfill definition from here.
 
    
    You could map the indices or for falsy values -1 and then filter all indices which are not -1.
var array = [true, true, false, false, false, true, false],
    result = array
        .map((b, i) => b ? i : -1)
        .filter(i => i !== -1);
        
console.log(result); 
    
    A potentially more elegant solution is:
[...arr.keys()].filter(i => arr[i])
or alternatively
[...arr.entries()].filter(([, v]) => v).map(([i]) => i)
 
    
    You can simply use a loop and check the boolean value true in your if condition:
var arr = [true, true, false, false, false, true, false];
var indexArray = [];
arr.forEach((val, index) => {
  if(val){
    indexArray.push(index);
  }
});
console.log(indexArray); 
    
    try this
var arr = [true, true, false, false, false, true, false];
var indexArray = [];
arr.forEach(function(value, index) {
    if (value) {
        indexArray.push(index);
    }
})
console.log(indexArray); 
    
     
    
    Different solution based on logic itself and not JS paradigms
let newArr = [];
for (let i = 0 ; i<indexArray.length;i++){
    if (indexArray[i]) newArr.push(i)
}
