Fetch data in iOS 12

Question

I have an error when I try to fetch data using Xcode 10 Beta and Swift 4.2.

In swift 4.1 was working perfect my method and now I have an error and I can't find a solution on internet to fix it.

Here is my code:

// Download photos from Google for products avatar
func fetchPhotosForProductsFromGoogle(){

    guard let requestURL = NSURL(string: URL.googleAPI + "q=\(query ?? "flagUK")" + URL.searchPhotosOnly + URL.googleSearchEngineID + URL.googleAPIKey)
        else{
            fatalError("URL can't be found.")
    }

    URLSession.shared.dataTask(with: requestURL) { (data, response, error) in

        guard error == nil else {
            print(error?.localizedDescription ?? "Error URL Session.")
            return
        }
        do {

            let googlePhotosList = try JSONDecoder().decode(GoogleSearchModel.self, from: data!)

        } catch {
            print(error.localizedDescription)
        }
        DispatchQueue.main.async {

            self.productsTableView.reloadData()
        }

        }.resume()
}

Here is a picture with the error:

Any idea will help me a lot ! Thanks.

Why did you needlessly start using `NSURL` instead of `URL`? — rmaddy, Jun 28 '18 at 16:00
FYI - It would be much better to build your `URL` using `URLComponents` instead of all of that string manipulation, especially the query string. — rmaddy, Jun 28 '18 at 16:01
@rmaddy Thank you maddy. I go now to check how to do it with URLComponents. — Florentin Lupascu, Jun 28 '18 at 16:05

score 1 · Answer 1 · answered Jun 28 '18 at 14:42

Before swift 3 there was implicit bridging between between swift types and their counter types in objc but after swift 3 it is removed and you will have to be explicit while passing such type, refer here for more details

So you can do this

with: requestURL as URL

Or Use URL instead of NSURL

score 0 · Answer 2 · answered Jun 28 '18 at 14:35

0

Change the NSURL to URL and I think you should be good to go:

guard let requestURL = URL(string: "someUrl.com")
    else{
        fatalError("URL can't be found.")
}

answered Jun 28 '18 at 14:35

Aaron

7,055
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I use NSURL because I'm not able to use URL. When I open the brackets after URL then I have only this 2 options: https://ibb.co/ncFWEo – Florentin Lupascu Jun 28 '18 at 14:41

score 0 · Answer 3 · answered Jun 28 '18 at 14:35

0

In the left part you send the URL object but in the right it's NSURL

func dataTask(with url: URL) -> URLSessionDataTask

see here in Docs

answered Jun 28 '18 at 14:35

Shehata Gamal

98,760
8
65
87

score 0 · Accepted Answer · answered Jun 28 '18 at 15:49

0

The problem was in a JSON Model where was a structure named URL and because of that structure the URL class from Swift was override. So be careful when you convert your JSON model into Swift to check 2 times the name of the structures, enums etc.

answered Jun 28 '18 at 15:49

Florentin Lupascu

754
11
30

Fetch data in iOS 12

4 Answers4