'str' object has no attribute 'pop'

Question

AttributeError: 'str' object has no attribute 'pop'

a = input('enter a list : ')
p = 2
i = 0
l = len(a)
while l>0:
    i = (p+i)%l
    print(a.pop(i))
    l -= 1

its showing 'str' object has no attribute 'pop' error .... so how can i solve it — smruti ranjan, Jul 07 '18 at 22:02
you must explain what you are trying to do, what is the expected behaviour... — Gelineau, Jul 07 '18 at 22:04
`input()`returns a string (unless you're using Python 2 where it returns a security hole). — Steven Rumbalski, Jul 07 '18 at 22:06
question is : Write a Python program to remove and print every third number from a list of numbers until the list becomes empty. — smruti ranjan, Jul 07 '18 at 22:10
if u will take a = [1,2,3,4,5] directly instead of a = input() it ll give u the answer bt i want it with input — smruti ranjan, Jul 07 '18 at 22:11
@smrutiranjan But there is no third number when the list has less than three items. Do you want to remove and print the last item instead in that case? — blhsing, Jul 07 '18 at 22:15
could you please edit your question to make clear what you are exactly asking? — smn.tino, Jul 07 '18 at 22:16

score 3 · Accepted Answer · answered Jul 07 '18 at 22:08

a is assigned a string returned by input(), so you need to turn it into a list first before you can use list methods such as pop() on it.

For example, by using a.split() you can treat a as a space-delimited string:

a = input('enter a list : ')
n = a.split()
p = 2
i = 0
l = len(n)
while l>0:
    i = (p+i)%l
    print(n.pop(i))
    l -= 1

Sample input and output:

enter a list : 3 5 2 1
2
5
1
3

1 Answers1