Split text from url

Question

I have this url

https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp

I need to get text of table name from the url when page loads. I tried this

location.href.split('&')[1]

It returns "table=user". but I need the table name alone as user.

How can I get this?

you can split the result using result.split('='); – Jagdeesh Kumar Jul 20 '18 at 10:33 — Jagdeesh Kumar, Jul 20 '18 at 10:33

score 3 · Accepted Answer · answered Jul 20 '18 at 10:34

3

Try using URL.searchParams

 // location.href
let str = "https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp"; 

console.log((new URL(str)).searchParams.get("table"));

answered Jul 20 '18 at 10:34

Nikhil Aggarwal

28,197
4
43
59

1

Please don't answer obvious duplicates. Close-vote them, instead. – Cerbrus Jul 20 '18 at 10:49

Justinas · Answer 2 · 2018-07-20T10:35:36.950

1

Split it once more:

location.href.split('&')[1].split('=')[1]

Or you could use Url class (no support in IE):

var url = "https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp"; //window.location.href
var url = new URL(url);
var table = url.searchParams.get("table");
console.log(table);

edited Jul 20 '18 at 10:35

answered Jul 20 '18 at 10:33

Justinas

41,402
5
66
96

Please don't answer obvious duplicates. Close-vote them, instead. – Cerbrus Jul 20 '18 at 10:34

score 0 · Answer 3 · answered Jul 20 '18 at 10:35

0

location.href.split('table=')[1].split('&')[0]

Don't assume the parameter order ;)

answered Jul 20 '18 at 10:35

Davesoft

724
1
4
10

Split text from url

3 Answers3