Write a function that accepts an array of test scores as an argument then the function should return a number of scores that 80 or higher?

Question

I'm still pretty new into JS but I'm having a hard time with this problem. I'm sure the answer is somewhat simple but i can't figure out what to put into the function expression after i've made my array of scores? Do i need to do a for loop? Thanks

array = [20,30,40,50,60,70,80,92,93,95,98,100]

 function testScores(array){

 }

See generally: https://stackoverflow.com/questions/3010840/loop-through-an-array-in-javascript — Michael W., Jul 25 '18 at 19:58
please add the result as well. do you need all values above or just a single value, the first or the smallest, or what ever? — Nina Scholz, Jul 25 '18 at 20:03

score 0 · Accepted Answer · answered Jul 25 '18 at 20:00

0

you can use array's filter method. please follow below definition.

function testScores(array){
 return array.filter(ele=>ele>=80)
}

answered Jul 25 '18 at 20:00

Manoj

1,175
7
11

He/She wants the number as output. – FullStackDeveloper Jul 25 '18 at 20:02
btw, `testScores` is plural. – Nina Scholz Jul 25 '18 at 20:07

emmatope · Answer 2 · 2018-07-25T20:03:05.083

0

function testScores(array){
  return array.filter(number => number >= 80);
}

This will return an array of scores more 80 and above. e.g

let scores = [20,30,40,50,60,70,80,92,93,95,98,100];
testScores(scores)

If you just want the count of scores more than 80 you can do

testScores(scores).length

edited Jul 25 '18 at 20:03

answered Jul 25 '18 at 20:00

emmatope

1
2

He/She wants the number as output. – FullStackDeveloper Jul 25 '18 at 20:02
btw, `testScores` is plural. – Nina Scholz Jul 25 '18 at 20:07

Write a function that accepts an array of test scores as an argument then the function should return a number of scores that 80 or higher?

2 Answers2