So yes it was difficult but i did it without any API
private static List<Class<?>> findClasses(File directory, String packageName) {
    List<Class<?>> classes = new ArrayList<Class<?>>();
    if (!directory.exists())
        return classes;
    File[] files = directory.listFiles();
    for (File file : files) {
        if (file.isDirectory()) {
            assert !file.getName().contains(".");
            classes.addAll(findClasses(file,
                    (!packageName.equals("") ? packageName + "." : packageName) + file.getName()));
        } else if (file.getName().endsWith(".class"))
            try {
                classes.add(Class
                        .forName(packageName + '.' + file.getName().substring(0, file.getName().length() - 6)));
            } catch (ClassNotFoundException e) {
                System.err.println(e.getMessage());
            }
    }
    return classes;
}
this returns all classes inside a package like TREE command in CMD (if you insert "" as packagne name this will return all classes inside the project).
public static Class<?>[] getClasses(String packageName) {
    ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
    assert classLoader != null;
    String path = packageName.replace('.', '/');
    Enumeration<URL> resources = null;
    try {
        resources = classLoader.getResources(path);
    } catch (IOException e) {
        System.err.println(e.getMessage());
    }
    List<File> dirs = new ArrayList<File>();
    while (resources.hasMoreElements()) {
        URL resource = resources.nextElement();
        dirs.add(new File(resource.getFile()));
    }
    List<Class<?>> classes = new ArrayList<Class<?>>();
    for (File directory : dirs)
        classes.addAll(findClasses(directory, packageName));
    return classes.toArray(new Class[classes.size()]);
}
then this method extract all classes from a package using findClasses() method.