How do I make a timer in python?

Question

I want a timer, but I want it to just affect one function, so it can't just be sleep().

For example:

def printSomething():
    print("Something")
def functionWithTheTimer():
    for i in range(0, 5):
        #wait for 1 second
        print("Timer ran out")

Say the first function is called when a button is clicked, and the second function should print something out every second, both should act independently.

If I used sleep(), I couldn't execute the first function within that one second, and that's a problem for me. How do I fix this?

Possible duplicate of [Run certain code every n seconds](https://stackoverflow.com/questions/3393612/run-certain-code-every-n-seconds) — , Aug 07 '18 at 11:30
This could be a duplicate of https://stackoverflow.com/questions/15167334/alternative-to-pythons-time-sleep — Mohl, Aug 07 '18 at 11:38

miike3459 · Accepted Answer · 2018-08-07T11:39:38.630

For your timer function, you may want to do something like this:

def functionWithTheTimer():
    for i in reversed(range(1, 6)):
        print(i)
        time.sleep(1)
    print("finished")

This will print the range backwards (like a countdown), one number every second.

EDIT: To run a function during that time, you can just duplicate and shorten the wait time. Example:

def functionWithTheTimer():
    for i in reversed(range(1, 6)):
        print(i)
        time.sleep(0.5)
        YourFunctionHere()
        time.sleep(0.5)
    print("finished")

You can play with the timings a little so you can get your appropriate output.

He said do not use sleep() – Saige Zhang Aug 07 '18 at 11:36 — Saige Zhang, Aug 07 '18 at 11:36

score 0 · Answer 2 · answered Aug 07 '18 at 11:38

0

You can use the datetime library like this:

from datetime import datetime

def functionwithtimer():
   start_time = datetime.now()
   # code stuff you have here 
   print("This function took: ", datetime.now() - start_time)

answered Aug 07 '18 at 11:38

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How do I make a timer in python?

2 Answers2