For example
System.out.println("a".substring(1) == "");
will return false.
However, it does return an instance of Stringsuch that println will display nothing. What is it and how to detect it, then?
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2here I can see a basic mistake, you can use ("a".substring(1)).equals("") – Swapnil Aug 09 '18 at 04:08
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2`System.out.println("a".substring(1).isEmpty());` – Elliott Frisch Aug 09 '18 at 04:16