What is wrong in below code?

Question

Program to find whether the given number is present in given list of numbers in python. What is wrong in below code? It never prints "number is present".

import sys

a = [1,2,3,4,5,6,7,8]
each = 1
s = raw_input("eneter a number ")

for each in range(0,len(a)):
    if s == a[each]:
        print "number is present"
        sys.exit()
    elif each == len(a):
        print "not present"
    else:
        continue

Why do you say something is wrong? Do not answer in comments, but in the question, using the [edit](https://stackoverflow.com/posts/51780524/edit) feature. — kabanus, Aug 10 '18 at 06:46
you can just check `if int(s) in a:` to see if it is in the list. — Bernhard, Aug 10 '18 at 06:48
Somewhat unrelated but you seem to be learning python. You really want to learn python3 instead of python2 as it will [retire soon](https://pythonclock.org/). — Fynn Becker, Aug 10 '18 at 07:49

score 2 · Answer 1 · answered Aug 10 '18 at 06:49

2

You can write your code in this way:

a = [1,2,3,4,5,6,7,8]
s = int(raw_input("enter a number "))
if s in a:
    print "number is present"
else:
    print "not present"

answered Aug 10 '18 at 06:49

Joe

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An additional hint explaining, that the string returned by `raw_input()` will never match the integers given in list `a` would complete this answer. – guidot Aug 10 '18 at 06:59

What is wrong in below code?

1 Answers1