Python regex extract number between forward slashes

Question

New to python and need help with regex please.

How do I extract the number 10000000000 from the string below

/s-seller/John/10000000000/time/1

Please note the word John is dynamic and number 10000000000 can also be any random numbers.

Thank you

That string contains two separate numbers. How do you decide which one do you want? — John Gordon, Aug 15 '18 at 01:27
Possible duplicate of [Reference - What does this regex mean?](https://stackoverflow.com/questions/22937618/reference-what-does-this-regex-mean) — pault, Aug 15 '18 at 01:30

score 3 · Answer 1 · answered Aug 15 '18 at 01:27

If you want to get the first number:

import re
regex = re.compile('.*\/(\d+)\/.*')
regex.match(your_str).group(1)

the (\d+) is a capture group that will match your number.

A simpler approach without regexes would be to split the string by /:

[int(d) for d in your_str.split('/') if d.isdigit()]

score 2 · Accepted Answer · answered Aug 15 '18 at 01:30

2

import re

line = "/s-seller/John/10000000000/time/1"

m = re.search(r'/(\d+)/', line)

print(m.group(1)) # 10000000000

the regex expression r'/(\d+)/' you can use.

answered Aug 15 '18 at 01:30

pwxcoo

2 Answers2