i am trying to archive pagination with single php sql query as i feel its too much running a select statement twice just because i want to paginate my data i have tried the query function (*)count 
i have tried just setting a limit and if the number_of_rows is equal to my limit i automatically paginate this works for two pages but i can't determine up to third page so its not a good approach.
another way i am thinking of is getting all the data then use java script to paginate but i have no idea how to do that so i am trying to do it with php but will like to learn how to do it with java script if possible.
i just want to run only one query and paginate thanks for your help
here is my code:
   <?php
    //count rows in table
    $query= "SELECT * FROM $database.$table WHERE `id` <> '$id'";
    $result= mysqli_query($conn, ($query));
    $results_per_page =30;
    //calculate total pages
    if($result)
    {
        $num_row = mysqli_num_rows($result);
        mysqli_free_result($result);
        $total_pages = ceil($num_row / $results_per_page);
    }   
    //to get page value
    if(isset($_GET["page"])){ 
        $page =$_GET["page"]; 
    } else{ 
        $page=1; 
    };
    $start_from = ($page-1) * $results_per_page;
    $start_from_here = mysqli_real_escape_string($conn, stripslashes($start_from));
    $start_from_here = filter_var($start_from_here, FILTER_SANITIZE_NUMBER_INT );
    //get data to display
    $query1= " SELECT * FROM $database.$table 
                WHERE `id` <> '$id' 
                ORDER BY type ASC 
                LIMIT $results_per_page OFFSET $start_from_here  ";
    $result1= mysqli_query($conn, ($query1));
and my html pagination code is like so
<?php
    if(isset($total_pages) && ($total_pages>1)) {   
        $url="http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
        $url=strtok($url, '?');
        for ($i=1; $i<=$total_pages; $i++) {   
        //Print links for all pages
            echo "<a class='pagination' href='".$url."?page=".$i."'>".$i."</a>";
        }
    }
    ?>
thank you for all your help