How to print list elements in one line?

Question

I need to print the sorted list of integers, but it should be in a line and without the list square brackets and without any '\n' in the end...

import random
n = int(input(""))
l=[]
for i in range(n):
    x = int(input())
    l.append(x)
not_sorted = True
while not_sorted:    
    x = random.randint(0,n-1)
    y = random.randint(0,n-1)
    while x==y:
        y = random.randint(0,n-1)
    if x>y:
        if l[x]<l[y]:
            (l[x],l[y])=(l[y],l[x])
    if x<y:
        if l[x]>l[y]:
            (l[x],l[y])=(l[y],l[x])
    for i in range(0,n-1):
        if l[i]>l[i+1]:
            break
    else:
       not_sorted = False
for i in range(n):
    print(l[i])

output should be like this::: 1 2 3 4 5 and not like this :::: [1,2,3,4,5]

Possible duplicate of [Python: multiple prints on the same line](https://stackoverflow.com/questions/5598181/python-multiple-prints-on-the-same-line) — AntiMatterDynamite, Aug 30 '18 at 12:40
@kyouma How is all the sorting code relevant to the question? — user2390182, Aug 30 '18 at 12:40
Does this answer your question? [Printing an int list in a single line python3](https://stackoverflow.com/questions/37625208/printing-an-int-list-in-a-single-line-python3) — Tomerikoo, Oct 18 '21 at 07:59

FHTMitchell · Accepted Answer · 2018-08-30T12:41:32.067

31

You can unpack the list to print using * which will automatically split by a space

print(*l)

if you want a comma, use the sep= argument

print(*l, sep=', ')

edited Aug 30 '18 at 12:41

answered Aug 30 '18 at 12:38

FHTMitchell

11,793
2
35
47

2

Is this only for Python 3.0 and later? This doesn't work for Python 2.7 – SQA777 Jul 08 '21 at 01:22
why on earth are you still using python 2.7?! It's over 10 years old! If you want to do this on python 2, you'll need to do `from __future__ import print_function`. – FHTMitchell Jul 13 '21 at 13:24
1

There are some Python packages that changed in Python 3.0, which would require a not-insignificant code change. Yes, Python 2.7 is over 10 years old. For 10+ years, I wrote code in Python 2.7. The code didn't just upgrade automatically when Python 3.0 came along. – SQA777 Jul 15 '21 at 23:13

score 4 · Answer 2 · answered Aug 30 '18 at 12:38

4

Use

for i in range(n):
    print(l[i], end=' ')

Or

print(*l, end=' ')

answered Aug 30 '18 at 12:38

Sreeram TP

11,346
7
54
108

score -1 · Answer 3 · answered Aug 30 '18 at 12:44

You can use join and list comprehensions for that. The only thing, items in a list should be strings, not integers

import random

n = int(input(""))
l = []

for i in range(n):
    x = int(input())
    l.append(x)

not_sorted = True

while not_sorted:    
    x = random.randint(0, n-1)
    y = random.randint(0, n-1)
    while x == y:
        y = random.randint(0, n-1)
    if x > y:
        if l[x] < l[y]:
            (l[x], l[y]) = (l[y], l[x])
    if x < y:
        if l[x] > l[y]:
            (l[x], l[y]) = (l[y], l[x])

    for i in range(0, n-1):
        if l[i] > l[i+1]:
            break
    else:
       not_sorted = False

print(', '.join([str(l[i]) for i in range(n)]))

score -1 · Answer 4 · answered Jan 18 '20 at 16:40

-1

For the list of string, I do it this way....

listChar = ["a", "b", "c", "d"]

someChar = ""

for n in listChar:
  someChar = someChar + n

print(someChar)

Res: abcd

answered Jan 18 '20 at 16:40

Matej89

1
1

score -1 · Answer 5 · answered May 22 '21 at 18:31

-1

Use enumerate to generate count(0-indexed) for each value. To print them on the same line use can use the end keyword

    for idx, val in enumerate(list_name):
         print(val, end = " ")

answered May 22 '21 at 18:31

Sarvesh Jayaraman

53
1
4

How to print list elements in one line?

5 Answers5

Linked