Pythonic way performing split on all elements of a list

Question

I want to end up with a list that contains the first elements of a split on all items of a list. That is. input_list = [‘A1 - Some Text’, ‘A2 - Other Text’] should result as output_list = [‘A1’, ‘A2’]. What is the most Pythonic (clever) way of doing this? Extra points for not needing multiple list variables.

UPDATE:

Updating with my initial attempt:

input_list = [‘A1 - Some Text’, ‘A2 - Other Text’]
output_list = []

for element in input_list:
    output_list.append(element.split(' - ')[0]))

Can you [edit your question](https://stackoverflow.com/posts/52122876/edit) to include your latest attempt(s)? — jpp, Aug 31 '18 at 21:42
Possible duplicate of [split elements of a list in python](https://stackoverflow.com/questions/6696027/split-elements-of-a-list-in-python) — jpp, Aug 31 '18 at 21:50

score 0 · Accepted Answer · answered Aug 31 '18 at 21:45

0

If l contains your list, I think something like: [i.split('-')[0] for i in l] should provide a good start.

answered Aug 31 '18 at 21:45

Hans Bouwmeester

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Thank you @Hans! This is exactly what I was looking for. – adamz88 Sep 05 '18 at 16:08

Pythonic way performing split on all elements of a list

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