How to find which value is closest to a number in Python?

Question

Is there any method in python to find which of two values is closet a given number?

Say i have two values such as 1.5 and 5.5, and i want to find which of them is closest to 3. Not using Lists

[How do I find the difference between two values without knowing which is larger?](https://stackoverflow.com/q/13602170) — Bernhard Barker, Sep 15 '18 at 11:07

user2390182 · Accepted Answer · 2018-09-15T10:43:49.453

1

You can use min with a key function, the abs of their respective difference to the compare key:

min((1.5, 3.5), key=lambda x: abs(3-x))
# 3.5

edited Sep 15 '18 at 10:43

answered Sep 15 '18 at 10:41

user2390182

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numbers are not in a list, Without using list. – user1779646 Sep 15 '18 at 10:42

Azhy · Answer 2 · 2018-09-15T11:01:09.567

-1

I don't know if there's a built-in function for doing this, but its so easy to do your self, for example:-

Edit:-

Sorry i made some simple wrongs first because of i am using a mobile phone and i cant compile it but i fixed them:-

def closer(n1, n2, main):
    if(abs(main-n1)>abs(main-n2)):
        return n2
    else:
        return n1

print(closer(1.5, 5.5, 3))

#the result is 1.5

edited Sep 15 '18 at 11:01

answered Sep 15 '18 at 10:47

Azhy

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How to find which value is closest to a number in Python?

2 Answers2