Referencing variable from a def block in another def block

Question

Basically I have this section of code that goes like so:

def start():

def blockA():
    y = 3
    x = 4
    print("hello")
blockA()

def blockB():
    if x !=y:
        print("not the same")
blockB()
start()

However, this gives me an error saying that x and y are not defined. How would I go about referencing the x and y variables in blockB?

You don't. Those are *local* variables. If you want data to be accessible outside of your function, you should *return that data from your function* — juanpa.arrivillaga, Sep 21 '18 at 19:43
@juanpa.arrivillaga how would i go about returning it and then referencing it in the next block? — Collette jorike, Sep 21 '18 at 19:46
[Calling variable defined inside one function from another function](https://stackoverflow.com/questions/10139866/calling-variable-defined-inside-one-function-from-another-function) — benvc, Sep 21 '18 at 19:53

score 1 · Accepted Answer · answered Sep 21 '18 at 19:52

1

You need to return the variables in blockA function and call that function in your second function.

def blockA():
    y = 3
    x = 4
    print("hello")
    return x,y


def blockB():
    x,y=blockA()
    if x !=y:
        print("not the same")

This should work for you.

answered Sep 21 '18 at 19:52

Ankur Gulati

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1
12

Perfect! Thank you so much! – Collette jorike Sep 21 '18 at 19:54
If the answer helped you please accept the answer and upvote it. Thanks in Advance :) – Ankur Gulati Sep 21 '18 at 19:55

Referencing variable from a def block in another def block

1 Answers1