Check if Groovy script is being executed directly

Question

In Python, one can check if a script is being invoked directly by checking if __name__ == '__init__'.

Is there any equivalent to this in Groovy?

Answer 1

I guess the easy way is to compare the current class name (using class.simpleName) to the actual executing file script name here is an example:

let's create the first class in M.groovy file:

class M {
    static main(args){
        def m = new M()
    }
    def M(){
        def thisClass = this.getClass().simpleName
        def callingClass = new File(getClass().protectionDomain.codeSource.location.path).name.with{ it.take(it.lastIndexOf('.')) }
        println("thisClass: ${thisClass}, callingClass: ${callingClass}")
        if (thisClass == callingClass){
            println 'Calling from M class...'
        } else {
            println 'Calling from outside.'
        }
    }
}

Now from external class e.g. T.groovy you can call an instantiate M class: new M(). when you execute M.groovy you got:

thisClass: M, callingClass: M
Calling from M class...

and when you run groovy T.groovy you'll get:

thisClass: M, callingClass: T
Calling from outside.

Hope this helps.