bash script failed to pass argument in linux

Asked Sep 29 '18 at 13:10

Active Sep 29 '18 at 13:20

Viewed 58 times

I have a bash script, the file name is deploy.sh so in my terminal I do

#!/bin/bash

if [ -n "$1" ]
then
  ssh root@101.181.42.10 << 'COMMAND'
    cd /var/www/myApp
    git pull
    npm i
    pm2 kill
    pm2 start pm2.json --env $1
COMMAND
else
  echo "argument is not set!"
fi

but I got this error error: option--env ' argument missing` which means $1 is not set, I wonder why, I tried this in my terminal

. deploy staging

then my bash I have

if [ -n "$1" ]
then
  ssh root@101.181.42.10 << 'COMMAND'
    echo $1
COMMAND
else
  echo "argument is not set!"
fi

I can see 'staging' been print. Am I concat the argument wrongly in my command?

edited Sep 29 '18 at 13:20

Cyrus

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asked Sep 29 '18 at 13:10

Alisa T Morgan

2

Don't use string delimitator on inline document: `< – F. Hauri - Give Up GitHub Sep 29 '18 at 13:16
Read bash's man page section `Here Documents`. – Cyrus Sep 29 '18 at 13:20
1

F. Hauri is correct: when you single-quote the here "word", you effectively single quote the entire here-doc, so your variables will not be expanded. – glenn jackman Sep 29 '18 at 14:59
2

Possible duplicate of [Using variables inside a bash heredoc](https://stackoverflow.com/q/4937792/1255289) – miken32 Sep 29 '18 at 15:46
1

Both these examples should be failing, and they do on my machine. Could you copy-paste your second example into a new file and run it as described to double check that you are indeed seeing `staging` with that exact snippet? – that other guy Sep 29 '18 at 16:35
@F.Hauri answered the question, that's the only mistake. – Alisa T Morgan Oct 01 '18 at 06:06

bash script failed to pass argument in linux

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