How can I call a method from base class

Question

class Base():
    def __init__(self):
        print("test")

    def first_func(self):
        print("first function call")


class Deriv(Base):
    def __init__(self):
        Base.__init__(self)

    def first_func(self):
        print("Test Derived")

C = Deriv()
C.first_func() # It gives output "Test Derived"

How can I call a first_func() method (output should be "first function call") from base class ( Class Base) using only object C and python 2.7 ?

You are currently doing something called "overriding" a method. Check this [article](http://blog.thedigitalcatonline.com/blog/2014/05/19/method-overriding-in-python/) out for more information about it! — Aquarthur, Oct 03 '18 at 09:29

rainer · Answer 1 · 2018-10-03T09:39:59.133

You can use Base.first_func(C) to explicitly call the base class function:

class Base():
    def __init__(self):
        print("test")

    def first_func(self):
        print("first function call")


class Deriv(Base):
    def __init__(self):
        Base.__init__(self)

    def first_func(self):
        print("Test Derived")

C = Deriv()
Base.first_func(C)

Output is:

test
first function call

If you were using new-style classes (ie., you had derived Base from object), using super is preferred, as mentioned in here.

How can I call a method from base class

1 Answers1