How to display a string of integers on multiple lines?

Question

My output is a string of integers, displayed consecutively on the same line. Preferably using backslash n, how can I make them be displayed, each on a new line? This is what I have this far:

string even = "";

        while (true)
        {
            string inputData = Console.ReadLine();
            if (inputData.Equals("x", StringComparison.OrdinalIgnoreCase))
            {
                break;
            }

            for (int i = 0; i < inputData.Length; i++)
            {
                if (inputData[i] % 2 == 0)
                {
                     even +=inputData[i];

                }
            }

        }
        foreach (var e in even)
            Console.WriteLine(e);
        bool something = string.IsNullOrEmpty(even);
        if( something == true)
        {
            Console.WriteLine("N/A");
        }
        Console.ReadLine();

So, string even, that contains all the even numbers from input should be seen on the console on different lines. Any help would be appreciated!

Answer 1

Simple console otuput:

foreach (var e in even)
    Console.WriteLine(e);

Html output

var result = "";

foreach (var e in even)
    result += e + "<br>\n";

return Content(result);

Answer 2

Use string.Join to create one string out of your numbers string (a string is a collection of characters so you can do so), and specify the separator as Environment.NewLine:

var result = string.Join(Environment.NewLine, even.AsEnumerable());

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As a side note, it is not advised to concat a string like that in a loop. Use StringBuilder. For explanations why see When to use StringBuilder? with the many linked questions.

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Also worth mentioning that though inputData[i] % 2 == 0 works for you you should remember that iputData[i] is a character and not an integer. Therefore the % operates on the ASCII representation of the character. For the cases of numbers it works as expected but for instance also A % 2 == 0 will work.

And if familiar with linq you can refactor is as follows:

var even = string.Join(Environment.NewLine, inputData.Select(c => c % 2 == 0));