Get caller function arguments

Question

How can I get the current function's caller function's arguments?

Answer 1

Use debug_backtrace function.

It generates a PHP backtrace, returning an array of associative arrays. One of the keys in those associative arrays is 'args'. If called inside a function, this key basically contains the functions arguments list (as an array). If this is used inside an included file, this lists the included file name(s).

For eg (from PHP docs):

function a_test($str)
{
    echo "\nHi: $str";
    var_dump(debug_backtrace());
}

a_test('friend');

It will output the following:

array(2) {
[0]=>
array(4) {
    ["file"] => string(10) "/tmp/a.php"
    ["line"] => int(10)
    ["function"] => string(6) "a_test"
    ["args"]=>
    array(1) {
      [0] => &string(6) "friend"
    }
}
[1]=>
array(4) {
    ["file"] => string(10) "/tmp/b.php"
    ["line"] => int(2)
    ["args"] =>
    array(1) {
      [0] => string(10) "/tmp/a.php"
    }
    ["function"] => string(12) "include_once"
  }
}

Answer 2

The topic you mentioned with your answer https://stackoverflow.com/a/9133897/3224296

function GetCallingMethodName(){
    $e = new Exception();
    $trace = $e->getTrace();
    //position 0 would be the line that called this function so we ignore it
    $last_call = $trace[1];
    print_r($last_call);
}

function firstCall($a, $b){
    theCall($a, $b);
}

function theCall($a, $b){
    GetCallingMethodName();
}

firstCall('lucia', 'php');