FileNotFoundException on Java

Question

i am trying to read the input of integers such as

on a .txt file, but i always get a FileNotFoundException. It will output the result

if i run the code below:

import java.io.File;
import java.io.FileNotFoundException;
import java.util.*;

public class umm {

    public static void main(String[] args) throws FileNotFoundException  {
        // TODO Auto-generated method stub


        Scanner scanner = new Scanner(new File("huhu.txt"));
        int [] tall = new int [100];
        int i = 0;
        while(scanner.hasNextInt())
        {
             tall[i++] = scanner.nextInt();
             System.out.print(tall[i]);
        }

        scanner.close();
    }

}

if i add the integers in the .txt file so that it will have 6 integers like this

it will output

doesn't this mean that the file exists and it can access it? but why does it keep saying FileNotFound?

Well. Because the file isn't found. Ensure you locate the file at the right path. You can print the current path during execution by, e.g. `System.out.println(Paths.get(".").toAbsolutePath());` — Mena, Oct 25 '18 at 13:59

score 0 · Answer 1 · answered Oct 25 '18 at 14:02

0

Use an absolute path for huhu.txt.

You can see where your program is looking for huhu.txt by running this code.

System.out.println("Working Directory = " +
              System.getProperty("user.dir"));

answered Oct 25 '18 at 14:02

Neo

79
6

i did this and changed the line into something like Scanner scanner = new Scanner(new File("C:\\Users\\eleanor\\workspace\\something\\huhu.txt")); but it is still giving me the FileNotFoundException though – eleanor Oct 25 '18 at 14:09
nevermind, i got it. thank you! – eleanor Oct 25 '18 at 14:11

score 0 · Accepted Answer · answered Oct 25 '18 at 14:08

Look at this code:

 tall[i++] = scanner.nextInt();
 System.out.print(tall[i]);

The array element you read is not the same as the one you print (you print the next one, because the i++ has increased the index).

This explains all the 0 you get.

It is unclear to me how you get the FileNotFoundException.

score 0 · Answer 3 · answered Oct 25 '18 at 14:08

0

thats because you print the next element in the array that is not yet affected ,so try this

 while(scanner.hasNextInt())
{
        tall[i] = scanner.nextInt();
        System.out.println(tall[i]);
        i++;
}

answered Oct 25 '18 at 14:08

Abdelilah el mottaki

1
1

FileNotFoundException on Java

3 Answers3