How to wait for the combination of a CSS and an XPath selector in Python WebDriver?

Question

I'd like to keep my selectors simple when possible, and only use XPath where absolutely necessary. So rather than waiting for an XPath like //*[@class='files']/tbody/tr[1]/th[text()='filename'] I'd rather want to wait for the combination of the simple CSS selector .files tbody tr:first-child and the simple XPath th[text()='filename'].

presence_of_element_located only takes a single locator, so presence_of_element_located((By.CSS_SELECTOR, '.files tbody tr:first-child'), (By.XPATH, 'th[text()='filename']')) is out.

I can't chain these functions either, so presence_of_element_located((By.CSS_SELECTOR, '.files tbody tr:first-child')).presence_of_element_located((By.XPATH, 'th[text()='filename']')) won't work.

Andersson · Accepted Answer · 2018-11-24T20:29:16.440

You can create your custom method:

def find_element_by_combo(self, ancestor_locator, descendant_locator, timeout=10, index=0):
    # Getting list of ancestors
    try:
        ancestors =  wait(self, timeout).until(EC.presence_of_all_elements_located(ancestor_locator))
    except:
        return None
    # Getting descendant
    for ancestor in ancestors:
        if ancestor.find_elements(*descendant_locator):
            return ancestor.find_elements(*descendant_locator)[index]

and use it as below

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver import Chrome

Chrome.find_element_by_combo = find_element_by_combo

driver = Chrome()
driver.get(URL)
driver.find_element_by_combo(('css', '.files tbody tr:first-child'), ('xpath', './th[text()="filename"]'))

But IMHO it's better just to use XPath for complicated situations

How to wait for the combination of a CSS and an XPath selector in Python WebDriver?

1 Answers1