BitmapSource to BitmapImage

Question

I need to parse the content of Clipboard.GetImage() (a BitmapSource) to a BitmapImage. Does anyone knows how can this be done?

score 38 · Accepted Answer · edited Aug 11 '16 at 15:53

38

I've found a clean solution that works:

BitmapSource bitmapSource = Clipboard.GetImage();

JpegBitmapEncoder encoder = new JpegBitmapEncoder();
MemoryStream memoryStream = new MemoryStream();
BitmapImage bImg = new BitmapImage();

encoder.Frames.Add(BitmapFrame.Create(bitmapSource));
encoder.Save(memoryStream);

memoryStream.Position = 0;
bImg.BeginInit();
bImg.StreamSource = memoryStream;
bImg.EndInit();

memoryStream.Close();

return bImg;

edited Aug 11 '16 at 15:53

Aric

319
7
27

answered Mar 17 '11 at 11:42

Jaime Oro

9,899
8
31
39

5

Is it necessary to use `bImg.StreamSource = new MemoryStream(memoryStream.ToArray());` instead of `bImg.StreamSource = memoryStream;` and removing `memoryStream.Close(); ` – Elmo Jan 07 '12 at 15:28
2

You should add bImg.Freeze() at the end to allow multithreaded calls, otherwise works perfect. – m1k4 Aug 08 '13 at 13:00
2

@Don'tForgettoUpvote: For me `bImg.StreamSource = new MemoryStream(memoryStream.ToArray());` was necessary, else it was throwing exception. – dotNET Jan 11 '14 at 16:22
2

What if a PNG image is in the clipboard? Should you use the PngBitmapEncoder then? – Fabian Bigler Dec 16 '14 at 12:15
1

@Elmo The changes were indeed required, without them, it was throwing exception for me too – Amir Mahdi Nassiri Nov 09 '17 at 15:31
1

Is this even lossless? – EFraim Aug 30 '20 at 04:41

score 2 · Answer 2 · edited Jan 07 '12 at 15:48

using System.IO; // namespace for  using MemoryStream

private static byte[] ReadImageMemory()
{
    BitmapSource bitmapSource = BitmapConversion.ToBitmapSource(Clipboard.GetImage());
    JpegBitmapEncoder encoder = new JpegBitmapEncoder();
    MemoryStream memoryStream = new MemoryStream();
    encoder.Frames.Add(BitmapFrame.Create(bitmapSource));
    encoder.Save(memoryStream);
    return memoryStream.GetBuffer();
}

// and calling by this example........
byte[] buffer = ReadImageMemory();

BitmapSource to BitmapImage

2 Answers2

Linked