Display only the element with no duplicate

Question

How can I return only the element/s with no duplicate in the list?

e.g.

list = [1,4,5,1,5] to [4]

You can find some very good clues on how to do this [here](https://stackoverflow.com/a/9836685/102937). — Robert Harvey, Nov 22 '18 at 03:07
Or from [another answer to the same question](https://stackoverflow.com/a/49865122/1270789), then `list(set(uniques)-set(dups))`. — Ken Y-N, Nov 22 '18 at 03:14
write a function `def uniques(x): a,b=np.unique(x,return_counts=1);return a[b==1]` then use it: `uniques( [1,4,5,1,5])` — Onyambu, Nov 22 '18 at 03:59
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score 0 · Answer 1 · answered Nov 22 '18 at 06:40

0

You can use Counter()

from collections import Counter as counter 
list = [1,4,5,1,5]
c = counter(list)

print(*[item for item, time in c.items() if time==1], sep='\n')

Output :

C:\Users\Desktop>py x.py
4

answered Nov 22 '18 at 06:40

Rarblack

4,559
4
22
33

we can do it in a more simple manner. – mohor chatt Nov 22 '18 at 07:21
for sure we can but simple doesn't always mean the fastest one – Rarblack Nov 22 '18 at 08:06

score 0 · Answer 2 · answered Nov 22 '18 at 07:23

0

def unique(list1):
for i in list1:
    if(list1.count(i)==1):
        return i 
list1 = [10, 20, 10, 30, 40, 40]  
print(unique(list1))


list2 =[1, 2, 1, 1, 3, 4, 3, 3, 5]  
print(unique(list2))

answered Nov 22 '18 at 07:23

mohor chatt

356
1
8

Display only the element with no duplicate

2 Answers2