How do I load PHP include conditionally?

Question

I have a page that displays an include depending on language selected. It works perfectly in Classic ASP, but I have converted to PHP and it is ignoring the IF condition completely. For example:

if ($Lang = "AR") {
    include 'inc_default_ar.php';
} elseif ($Lang = "CN") {
    include 'inc_default_cn.php';
} elseif ($Lang = "CS") {
    include 'inc_default_cs.php';
} else {
    include 'inc_default_en.php';
}

Even though $Lang = "EN" it somehow displays the AR include, even though it is not a match.

score 4 · Accepted Answer · answered Dec 05 '18 at 01:01

4

You should use == to check for equality.

if ($Lang == "AR") {
    include 'inc_default_ar.php';
} elseif ($Lang == "CN") {
    include 'inc_default_cn.php';
} elseif ($Lang == "CS") {
    include 'inc_default_cs.php';
} else {
    include 'inc_default_en.php';
}

answered Dec 05 '18 at 01:01

pew007

453
2
7
17

This worked. I''l run with this because my code needs the "else" fallback. – WilliamK Dec 05 '18 at 01:41

Beans · Answer 2 · 2018-12-05T03:18:33.123

3

I agree with @pew007's answer. But if you change up your code a little bit and always have the $Lang variable set you could do something like the following.

include "inc_default_".strtolower($Lang).".php"

edited Dec 05 '18 at 03:18

answered Dec 05 '18 at 01:05

Beans

379
4
13

1

I think ``strtolower($Lang)`` might be the more appropriate choice given OP's code. – kmoser Dec 05 '18 at 01:23
$Lang and $LangCode (ie: "_en" are available) – WilliamK Dec 05 '18 at 01:35
This worked when I corrected your typo :-) – WilliamK Dec 05 '18 at 01:38
Oops wrong function. I've updated my answer, thanks @kmoser – Beans Dec 05 '18 at 03:19

How do I load PHP include conditionally?

2 Answers2