Easy way to parse Key value pair json

Question

I want to parse the json . I know retrofit and working on it, but don't know how to parse the below json as it is not in correct format.

Kindly help me in solving this. Number of Universities in the json is not static they will change .

{
    "transactionid": "7ec7d209589ce2abdb2e555c26776c85",
    "returncode": "200",
    "returnmsg": "success",
    "university": {
        "1": "Anna University",
        "3": "Technological University",
    }
}

I want to parse this json. I dont know how to create pojo for this json as it is having a structure of key values. — Senthilvel S, Dec 07 '18 at 09:15
paste your json here and get POJO zip file. http://www.jsonschema2pojo.org/ — Jay Dangar, Dec 07 '18 at 09:16
are you the one writing the api ? you need to change the 'university' field to an array else it's a pain to get the data — Oussema Aroua, Dec 07 '18 at 09:19
nope i asked my team to change the json as follows "university": { "id":"1, "name": Anna University" } but they told they cant change as we are using same api for all platforms. — Senthilvel S, Dec 07 '18 at 09:20
@OussemaAroua yes bro I know that will work like a charm ,but cant change the json now. :-( — Senthilvel S, Dec 07 '18 at 09:24
i tried that already it wont give proper pojo class for this json. — Senthilvel S, Dec 07 '18 at 09:28
Retrofit has nothing to do with parsing, it is made for network requests, not parsing. — Vladyslav Matviienko, Dec 07 '18 at 09:30
Please check this link `https://stackoverflow.com/questions/24279245` — Rujul Gandhi, Dec 07 '18 at 09:33
create a university class with two hashmap fields instead of changing university to an array — Milad Yarmohammadi, Dec 07 '18 at 09:37

score 1 · Accepted Answer · answered Dec 07 '18 at 09:48

You can use JsonDeserializer, import in you gradle file

com.squareup.retrofit2:converter-gson:2.1.0

and use class below

 public static class MyDeserializer implements JsonDeserializer<YourResponseModel> {

    @Override
    public YourResponseModel deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
        YourResponseModel response = new YourResponseModel();
        JsonObject jsonObject = json.getAsJsonObject();
        JsonObject university = jsonObject.getAsJsonObject("university");
        ArrayList<String> universities = new ArrayList<>();
        try {
            JSONObject object = new JSONObject(university.toString());
            Iterator<String> iter = object.keys();
            while (iter.hasNext()) {
                String key = iter.next();
                try {
                    String value = object.getString(key);
                    universities.add(value);
                } catch (JSONException e) {
                    Log.e(TAG, "deserialize: ",e );
                }
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
        response.university = universities;
        return response;
    }
}

Create new GsonBuilder for the JsonDeserializer

Gson gson = new GsonBuilder()
                .registerTypeAdapter(YourResponseModel.class, new MyDeserializer())
                .create();

and finally set it to the Retrofit Builder

 Retrofit retrofit = new Retrofit.Builder()
                .baseUrl(BASE_URL)
                .addConverterFactory(GsonConverterFactory.create(gson))
                .build();

You can get more information from this blog

Easy way to parse Key value pair json

1 Answers1