Variable data How to send thourgh ajax

Question

When I sent the variable data through ajax loading_add.php page an error is displayed:

Uncaught ReferenceError: profit is not defined.

What I tried so far is attached below.

var profit = (
  Number($("#pro_price").val() - retail_price)
);

$.ajax({
  type: "POST",
  url: '../php/product/loading_add.php',
  dataType: 'JSON',
  data: {
      profit: profit
  };

Nobody will be able to help if you don't post your server side code. — Georgi Georgiev, Dec 14 '18 at 06:48
Try to debug: what does the profit variable return? If its NAN try to add parseInt and check — Revathi Ganesh, Dec 14 '18 at 07:03
function profit () { var profit = ( Number($("#pro_price").val() - retail_price ) ); console.log(profit ); } }); here output diplayed success — Programmer Hari, Dec 14 '18 at 07:08
Obviously you had an error in your JS code, try to figure out where your variable had been created and changed before AJAX request — Volodymyr Mokhonko, Dec 14 '18 at 07:10
@ProgrammerHari Are you making your AJAX request in the same function? — Volodymyr Mokhonko, Dec 14 '18 at 07:11
@ProgrammerHari Seems like you trying to get `profit` out of it's scope. Have a look at https://www.w3schools.com/js/js_scope.asp — Volodymyr Mokhonko, Dec 14 '18 at 07:15

score 1 · Accepted Answer · answered Dec 14 '18 at 07:51

1

In you php page just define variable as:

@$_POST['profit'];

you will not get undefined error again, hope this trick will help you :)

answered Dec 14 '18 at 07:51

Therichpost

1,759
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Syamsoul Azrien · Answer 2 · 2018-12-14T07:05:35.253

0

Your question is not clear.

But I share the valid way to send data via AJAX and retrieve the data in PHP Server Side..

var profit = (
    Number($("#pro_price").val() - retail_price)
);

console.log(profit); // see in console log if `profit` is a valid variable or not
$.ajax({
    type: "POST",
    url: '../php/product/loading_add.php',
    dataType: 'JSON',
    data: {
        profit: profit
    }
}).done(function(result){
    //do something after done AJAX
});

In server side, you must call variable $_POST['profit'] to retrieve the profit value.

edited Dec 14 '18 at 07:05

answered Dec 14 '18 at 06:51

Syamsoul Azrien

2,534
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i tried sir Uncaught ReferenceError: profit is not defined – Programmer Hari Dec 14 '18 at 06:53
If you follow my code, there's nothing wrong at all.. maybe there's something wrong in your actual code.... let's try to put hardcode value on `profit`... `data: {profit: 23)`... see if it works... – Syamsoul Azrien Dec 14 '18 at 06:56
Uncaught ReferenceError: profit is not defined . ajex error sir – Programmer Hari Dec 14 '18 at 06:57
profit: 23 if i put like this data successfully goes to the page. how to define the variable sir . this is doen't work profit: profit – Programmer Hari Dec 14 '18 at 06:59
try `console.log(profit);` before AJAX..and see in DevTools (Console Tab) , what value it'll give... – Syamsoul Azrien Dec 14 '18 at 07:04
out put displayed 5 – Programmer Hari Dec 14 '18 at 07:12
maybe your actual code got problem...you can refer to this topic for `undefined variable` issue... https://stackoverflow.com/questions/17583544/referenceerror-variable-is-not-defined – Syamsoul Azrien Dec 14 '18 at 07:19
@ProgrammerHari,,, can you share what is the actual problem and what is the solution....and please mark the correct answer .... – Syamsoul Azrien Dec 14 '18 at 09:35

Variable data How to send thourgh ajax

2 Answers2