Comparing Time - Python

Question

I have a function where I read the time from a file. I put this into a variable. I then subtract this value from the current time which most of the time will give me a value around .

My problem is im not sure how to check if this value which I attach to a variable is greater than say 20 seconds.

def numberchecker():
    with open('timelog.txt', 'r') as myfile:
        data=myfile.read().replace('\n','')

    a = datetime.strptime(data,'%Y-%m-%d %H:%M:%S.%f')
    b = datetime.now()
    c = b-a   (This outputs for example: 0:00:16.657538)

    d = (would like this to a number I set for example 25 seconds)


    if c > d:
        print ("blah blah")

score 0 · Answer 1 · answered Dec 19 '18 at 13:50

0

The difference which you're getting is a timedelta object.

You can just use c.seconds to get the seconds.

answered Dec 19 '18 at 13:50

DM_Morpheus

710
2
7
20

Added comment to wrong answer. And I did that and still get error – user401708 Dec 19 '18 at 13:54
Use `c.seconds > d` instead of just `c > d` – DM_Morpheus Dec 19 '18 at 13:56

Fraser · Accepted Answer · 2018-12-19T14:06:53.370

-1

if c.total_seconds() > datetime.timedelta(seconds=d):
    print ("blah blah")

edited Dec 19 '18 at 14:06

answered Dec 19 '18 at 13:50

Fraser

91
8

when I assign an int to d (e.g.10), I then get the error TypeError: unorderable types: datetime.timedelta() > int() – user401708 Dec 19 '18 at 13:56
convert d to a timedelta: `datetime.timedelta(seconds=d)` – Fraser Dec 19 '18 at 14:04

Comparing Time - Python

2 Answers2