How do i check if my array contains a word that has spaces in it?

Question

int num;
num = in.nextInt();
String array[] = new String[num];
for (int i = 0; i < num; i++) {
    array[i] = in.next();
    if (array[i].equals("hey guys"))
        System.out.println("hey guys");
    else
        System.out.println("buzz");
}

This is the code i tried. When i remove the space in "hey guys", it works allright but otherwise it doesn't.

[Read it carefully](https://stackoverflow.com/questions/22458575/whats-the-difference-between-next-and-nextline-methods-from-scanner-class) you should use nextLine() method. — Rajan saha Raju, Jan 19 '19 at 11:57

score 1 · Answer 1 · edited Jan 19 '19 at 12:13

1

Just use in.nextLine() instead of in.next(). It will take line input including spaces.

int num;
num = in.nextInt();
String array[] = new String[num];
for (int i = 0; i < num; i++) {
    array[i] = in.nextLine();
    if (array[i].equals("hey guys"))
        System.out.println("hey guys");
    else
        System.out.println("buzz");
}

edited Jan 19 '19 at 12:13

Manoj Choudhari

5,277
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answered Jan 19 '19 at 12:00

Rajan saha Raju

794
7
13

Oh yeah how did i miss that? Thanks ! – Naeema Ibrahim Jan 19 '19 at 18:20

Ratish Bansal · Answer 2 · 2019-01-19T12:03:04.467

0

You can use contains() method from String class to check if the string has spaces in it.But from what I understood,you are facing the issue while reading the string with spaces.You should read in using in.nextLine()

int num;
num=in.nextInt();
String array[]=new String[num];
for(int i=0;i<num;i++){
array[i]=in.nextLine();
if(array[i].contains(" "))
//contains space
else 
System.out.println("buzz");}

edited Jan 19 '19 at 12:03

answered Jan 19 '19 at 11:55

Ratish Bansal

1,982
1
10
19

Thanks! That was helpful! – Naeema Ibrahim Jan 19 '19 at 18:21

How do i check if my array contains a word that has spaces in it?

2 Answers2