Count +1 when specific element present in an array

Question

We have an array and we count a variable to +1 if number specific element found in an array. It gives an output 0.

Any help Why .?

let arr = ['a', 'b', 'c', 'a', 'a',];

 let a = 0;

if (arr === 'a') {
 return a = a + 1;
} else {
return 'Invalid'; 
}

//Output is 0

It will return `invalid` because `arr` is an array, and is not `===` to `'a'`. The output is *not* `0`. — CertainPerformance, Jan 19 '19 at 21:38
@rayvic `===` doesn't check if an array contains a value, it checks if the two objects are equal. `'a'` is not equal to the entire array, so it's false. — Carcigenicate, Jan 19 '19 at 21:42
@radarbob reduce() gives the total output value and add all the elements present in an arrray . — rayvic, Jan 19 '19 at 21:42
@rayvic, I'm thinking something like this `arr.reduce( (acc, ele) => if( ele === "x") acc++ )` — radarbob, Jan 19 '19 at 22:28

score 0 · Answer 1 · answered Jan 19 '19 at 21:42

0

You need to iterate the items of the array and check the value of it.

By taking the return statement, you exit the function, which is actually not given. More than that, you want to count the other 'a' as well.

let arr = ['a', 'b', 'c', 'a', 'a', ],
    a = 0,
    i;

for (i = 0; i < arr.length; i++) {
    if (arr[i] === 'a') {
        a = a + 1;
    }
}

console.log(a);

answered Jan 19 '19 at 21:42

Nina Scholz

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It is not clear, but i don't think he want to count the number of `a` elements, for the code he made I think he want to just check if exists – Shidersz Jan 19 '19 at 21:45
i think op wants to count all `'a'` items. – Nina Scholz Jan 19 '19 at 21:46
Maybe, but why the return of `Invalid`? – Shidersz Jan 19 '19 at 21:48
who knows ... it? – Nina Scholz Jan 19 '19 at 21:51

Count +1 when specific element present in an array

1 Answers1