How to get ASCII representation of a character?

Question

I have very basic question. How is possible for int a = 'a' to give 97 in output.

Below is my code:

class myClass {
    int last = 'a' ;

    myClass () {
        System.out.println(last );
    }

}

Possible duplicate of [Java - char, int conversions](https://stackoverflow.com/questions/21317631/java-char-int-conversions) — Duck Dodgers, Jan 23 '19 at 08:30
So, What now? Are you going to delete the question or aprove one of the answers or close the question? — Akiner Alkan, Jan 23 '19 at 08:48

score 2 · Answer 1 · answered Jan 23 '19 at 08:35

2

You can have a look at this: Why are we allowed to assign char to a int in java?

Basically, you are assigning a char to your int. A char is technically an unsigned 16-bit character. That's why you can assign it to an int.

Hope this helps.

answered Jan 23 '19 at 08:35

Ben

66
5

score 1 · Answer 2 · answered Jan 23 '19 at 08:32

You can basically cast the char to the int and store it as int:

  int a = (int)'a';
  System.out.println(a); //prints 97

Since Java can do the basic castings from your type specifications, you do not need to explicity write casting even.

  int a = 'a';
  System.out.println(a); // prints 97

score 0 · Answer 3 · answered Jan 23 '19 at 08:32

0

The output is the ASCII value of the character stored in last. The ASCII value of the character 'a' is 97, and hence the output on the console is 97.

answered Jan 23 '19 at 08:32

Shreyas Nisal

39
3

score 0 · Answer 4 · answered Jan 23 '19 at 08:49

0

you have to take 'a' as a char char char1 = 'a'; then cast it to int int num = (int) char1 ;

answered Jan 23 '19 at 08:49

Khizar Sulehri

36
2

1

This is not entirely correct, eg consider what happens if the character is not in ASCII: you'll still get an integer value. – Mark Rotteveel Jan 23 '19 at 10:17

How to get ASCII representation of a character?

4 Answers4