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  • I have a model with a FileField namely file_test
  • I would like to manually create a file and assign in to file_test in the serializer

  • Below are my code, would like some help. Thanks

    class Test(models.Model):
    file_test = models.FileField(storage=OverwriteStorage(),
                              upload_to=_get_landmark_upload_path, max_length=100, blank=True)

class TestSerializer(serializers.ModelSerializer):
    test = serializers.CharField(write_only=True, required=True)

    class Meta:
        model = Test
        fields = ('file_test','test')

    def save(self, *args, **kwargs):
        self.file_test.save('test.txt', ContentFile(self.validated_data['test']))
        return super().save(*args, **kwargs)

  • Or is there a way to create a file and assign it to file_test?

  • example in serializer

    def save(self, *args, **kwargs):
    kwargs['file_test'] = ?????(how to create this file)
    return super().save(*args, **kwargs)
Ahtisham
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nicker
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  • https://stackoverflow.com/questions/50575902/saving-base64imagefield-type-using-django-rest-saves-it-as-raw-image-how-do-i-c/50693479#50693479 Use this solution `Base64ImageField` – Anup Yadav Jan 25 '19 at 06:58

1 Answers1

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  • I'd manage to solve the issue by using ContentFile

  • Look at example below

    def save(self, *args, **kwargs):
    kwargs['file_test'] = ContentFile(
        self.validated_data['test'], name="test.txt")
    return super().save(*args, **kwargs)
nicker
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