how to exclude a certain folder when using scandir in php

Question

I am using scandir to list all the files in a directory. But there should be an exception for ./, ../ and tmp folder.

I already have this to exclude the dot and double dot:

$files = preg_grep('/^([^.])/', scandir($dir));

How can i add tmp folder to it? (name of the folder is tmp)

As an aside: the code you're using will exclude _any_ file or directory whose name starts with a dot. This may or may not be something you actually want. — , Feb 01 '19 at 21:08
i agree.! But a name started with a dot is not allowed. It is filtered in the input — Jack Maessen, Feb 01 '19 at 21:10

score 1 · Answer 1 · edited Sep 08 '20 at 16:24

1

Try :

   $toRemove = array('.','..','tmp'); 

   $cdir = scandir($dir);
   
   $result = array_diff($cdir, $toRemove);

It's easier than preg_grep

edited Sep 08 '20 at 16:24

Amine KOUIS

answered Feb 01 '19 at 21:05

Vinz

score 1 · Answer 2 · answered Feb 01 '19 at 21:34

1

I would choose for this solution, because of already mentioned by @duskwuff, your current code excludes all the files which start with a .

$files = array_diff( scandir($dir), array(".", "..", "tmp") );

answered Feb 01 '19 at 21:34

mudraya

1

I agree! this is the better way to do it. works fine! – Jack Maessen Feb 01 '19 at 21:39

score 0 · Answer 3 · answered Feb 01 '19 at 21:22

0

Since it's a regex you can try to take a look at the negative lookahead:

$files = preg_grep('/^(?!tmp|\.{1,2})$/', scandir($dir));

answered Feb 01 '19 at 21:22

score 0 · Answer 4 · answered Feb 01 '19 at 21:31

0

I would have done something like that if you want to stick with regex

$files = preg_grep('/^(?!tmp|(?!([^.]))).*/', scandir($dir));

answered Feb 01 '19 at 21:31

Dialex

4 Answers4