I am trying to use strtok to break a simple equation like 5 + 4 down and store each part into an array, and once I have done this, perform the operation indicated.
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
//#include "stdafx.h"
int main() {
    char uin[10], op[10], error = 'e';
    char *token;
    const char s[2] = " ";
    double num1, num2, fNum1, res;
    int i = 0;
    int x, y, z, a, b, c, op1;
    printf("Welcome to the calculator, please enter an equation\n");
    while (error == 'e') { // & assigns address and * gives access to what it points to
        a = &uin[0];
        b = &uin[2];
        c = &uin[4];
        gets(uin);
        rewind(stdin);
        printf("Is this what you entered? %s\n", uin);
        token = strtok(uin, s);
        //x = &token;
        //printf("The element in the array currently assigned to token is: %s\n", token);
        while (token != NULL) {
            if (isdigit(token[0])) {
                num1 = atof(token);
                printf("token is now: %1.2f\n", num1);
            } else
                strcpy(op, token);
            token = strtok(NULL, s);
            if (isdigit(token[0])) {
                num1 = atof(token);
            } else
                strcpy(op, token);
            //token = strtok(NULL, s);
            //y = &token;
            //printf("The element in the array currently assigned to token is: %s\n", token);
        }
        //token = strtok(NULL, s);
        //y = &token;
        //printf("The element in the array currently assigned to token is: %s\n", token);
        //token = strtok(NULL, s);
        //z = &token;
        //printf("The element in the array currently assigned to token is: %s\n", token);
    }
    system("pause");
}
I am really having a hard time with this. I think that I am using strtok correctly to take the first part of the gets(uin) and storing it, but I don't understand how to take the middle part (+ - * or /) and store it.
