how to exit from set of loops at once and going back to the first loop?

Question

when the condition in last "IF STATEMENT" is satisfied for the first j, first g and first s, i want to break all 3 loops containing j, g and s and the code should try next i. If the last "IF STATEMENT" is not satisfied, the code should try next s, next g and next j respectively.

I tried using a flag variable. but it does not give me the result i want. I have made a mistake somewhere. Please help me out to solve this issue. I'm running out of time and really stressed about this matter since i have limited knowledge in python. I would be much grateful if you could sort this problem.

for i  in range(len(A.hp)):
   gg= False
   while gg==False:
     for j in range(len(run_parameters.bits_Mod)):
      req_slots[j] = math.ceil((A.T[i]["Traffic"])/(run_parameters.bits_Mod[j]*C))

      for g in Temp[i]["Available_ranges"][j]:
       for s in range(g[0], g[-1]):
          if (s+req_slots[j]-1) <= g[-1]:
             if (Temp[i]['cost'][j] <= (run_parameters.PSD)/(run_parameters.OSNR_threshold[j])):
               served_count +=1
               A.T[i]["First_index"]= s
               A.T[i]["Last_index"]= s+req_slots[j]-1
               A.T[i]["Status"]= 1
               A.T[i]["Selected_MOD"] = j
               gg=True

just a hint, make a function for the inner two loops,that returns when the condition satisfied and take loops variables as input, that should work.. — Yasin Yousif, Feb 11 '19 at 03:25

how to exit from set of loops at once and going back to the first loop?

0 Answers0