I have a form loaded from AJAX. On this form there is a input type button which i would like to manage like it
$("#button_id").on("click",function(){..}); 
but it's does not work...
My question is how to do this work?
Javascript/Jquery load form code
function openForm('commandForm')
{
    $.ajax({
        type: "POST",
        url: "./forms/commandForm.php",
        data: $('#'+frm).
        dataType: "html",
        beforeSend: function(msg){
            $('#ResponseDiv').html('Loding....');
        },
        success: function(back_data){
            $('#ResponseDiv').html(back_data);
        }
    });
}
commandForm.php
<form id="commandForm" action="postCommand.php" method="post" >
    .....
    ....
    <button type="Button" id="postButton" />
</form>
Jquery on postButton onclick
$(document).ready(function () {
    $('#postButton').on("click", function (e) {
        /*....*/
    });  //This don't work
}
PS: I don't want submit the form directly! Just make my own checkform running in my javascript function...out of here. So i want only that the button react on the Onclick ...so to do an alert for example or any javacript function else
