Sed substitution with quit giving only first line of file

Asked Feb 25 '19 at 09:02

Active Feb 25 '19 at 09:25

Viewed 177 times

I am trying to substitute timeout, and return 1 if the substitution fails.

abc.conf:

Title: ABC.conf
timeout : 10

sed command and output:

$ sed '/timeout/{s/timeout .*/timeout 100/g;Q};q1' abc.conf
$ Title:ABC.conf

But, sed fails to substitute returned 1, and in the output I only get the first line of the file.

What am I missing?

edited Feb 25 '19 at 09:25

Emma

asked Feb 25 '19 at 09:02

TheBeginner

1

Try `sed '/timeout .*/,${s//timeout 100/;b};$q1' abc.conf` – Wiktor Stribiżew Feb 25 '19 at 09:27
2

Possible duplicate of [Return code of sed for no match](https://stackoverflow.com/questions/15965073/return-code-of-sed-for-no-match) – Wiktor Stribiżew Feb 25 '19 at 09:28
2

The `q` command tells `sed` to stop processing the file there and then. You have it outside the braces, so it isn't governed by any condition. Therefore, it triggers unconditionally on the first line. – tripleee Feb 25 '19 at 09:28
@WiktorStribiżew thanks that worked, can you please explain whats happening here? – TheBeginner Feb 25 '19 at 09:32
It is explained [here](https://stackoverflow.com/a/15966279/3832970) very well. – Wiktor Stribiżew Feb 25 '19 at 09:33
Yes it is, very well thanks @WiktorStribiżew – TheBeginner Feb 25 '19 at 09:38

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