How to replace the last 14 number with 0s using regular expressions?

Question

I am displaying data from a file by using a regular expression. I want to use:

ID=02141592cc0000000700000000000000 
ID=02141592cc000000010000000e9489c5 
ID=02141592cc0000000500000000000000 
ID=02141592cc000000010000000e9489c5
ID=02141592cc0000000400000000000000 
ID=02141592cc000000010000000e9489c5

I am using this funtion to extract data:

data = OrderedDict({

    'data': r'\b\s\sID=(\w{32})0*',
   })

def Extract_List_Data_Info_Based_On_Regular_Expression(Log_File):
    # print(re_key)
    for re_key in data.keys():

        print(re_key)
        re_value = data[re_key]
        fsrc = open(Log_File, 'r')
        buff = fsrc.read()
        list_info = re.findall(re_value, buff)
        print(list_info)

My goal is to extract data, then modify the last 14 numbers with 0. I want write the modification in the file. For example: this ID=02141592cc000000010000000e9489c5 then I want to modify it it to ID=02141592cc0000000100000000000000

@JackMoody could you give me more exlpanation? It is not clear — Sony, Mar 01 '19 at 10:06
my answer wasn’t exactly right. You probably want to use `my_string = my_string[:-14] + “0”*14`. This will take your original string, cut off the last 14 characters and then add 14 zeros. — Jack Moody, Mar 01 '19 at 10:10
Possible duplicate of [Remove final character from string (Python)](https://stackoverflow.com/questions/15478127/remove-final-character-from-string-python) — Jack Moody, Mar 01 '19 at 10:15

Amit Nanaware · Accepted Answer · 2019-03-01T10:13:23.587

3

This will work for you

s1 = "ID=02141592cc000000010000000e9489c5"
print s1[:-14] + '0'*14

edited Mar 01 '19 at 10:13

answered Mar 01 '19 at 10:07

Amit Nanaware

3,203
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score 0 · Answer 2 · answered Mar 01 '19 at 10:13

0

I will write another answer, similar to Amit with repace()

ID = ID.replace(ID[len(ID)-14:], "0"*14)

That's the same idea behind. You don't need regular expression to do what you wanna do :)

answered Mar 01 '19 at 10:13

Maxouille

2,729
2
19
42

How to replace the last 14 number with 0s using regular expressions?

2 Answers2