How to POST data from value of input if its exist in echo

Question

I have a input inside of <form action="include_php/update.inc.php" method="POST"> </form>like this

<input type="text" id="username" name="new-username" value="<?php echo $result['user_name']?>">
<input type="text" id="password" name="new-password" value="<?php echo $result['user_password']?>">

And i am trying to read value of this input to check something. Here is the Post Codes.

When i try to only update my password. It goes first if even if there is a data inside of it.

$userName=$_POST['new-username'];
$userPassword=$_POST['new-password'];
    if($_SESSION['userName'] !== $userName){
        $sql="UPDATE users SET user_name='$userName' WHERE user_id='$id'"; 
        $query=mysqli_query($conn,$sql); 
    }
    elseif($_SESSION['userPassword'] !== $userPassword){
         $sql="UPDATE users SET user_password='$userPassword' WHERE user_id='$id'"; 
         $query=mysqli_query($conn,$sql);
        header("Location:http://localhost/talktoworldx/Anasayfa/account/index.php#success=update");
    }

But $userName has already value from database but it return nothing. and it becomes like this if($_SESSION['userName'] !== "" )and it goes first if and change username to empty.

Maybe i am making really small mistake here but i couldnt figure out this.

So how can i send this value as POST method ?

`
` be default makes a GET request, not POST. You need to specify `method="POST"` in your form element to use POST. — Jonnix, Mar 06 '19 at 15:49
One other option, if it fits the need, I recently learned of is to use PHP's $_REQUEST superglobal. You can read about it here: http://php.net/manual/en/reserved.variables.request.php — Michael, Mar 06 '19 at 15:52
using `$_REQUEST` is a bad Idea as it can be overridden by `$_COOKIE` on some PHP applications. See. https://stackoverflow.com/questions/2142497/whats-wrong-with-using-request — ArtisticPhoenix, Mar 06 '19 at 15:55
It's kind of a "sticky wicket" Something that would be great to use, but has all kinds of hidden pitfalls. Generally I just avoid it. `A sticky wicket (or sticky dog, or glue pot) is a metaphor used to describe a difficult circumstance.` — ArtisticPhoenix, Mar 06 '19 at 15:57

prasanth · Answer 1 · 2019-03-06T16:01:08.663

2

Try with method attr of form set as post

<form method="post" action="url">
 <input type="text" id="username" name="new-username" value="<?php echo $result['user_name']?>">
</form>

FOR php

To validated the post data before

$userName=isset($_POST['new-username']) ? $_POST['new-username'] :''; 
if(!empty($userName){
 //do all stuff
}

edited Mar 06 '19 at 16:01

answered Mar 06 '19 at 15:50

prasanth

22,145
4
29
53

@FurkanAkgün ok.What is the action ? can you post you form markup – prasanth Mar 06 '19 at 15:51
are you sure.you could add this code in `include_php/update.inc.php` page – prasanth Mar 06 '19 at 15:56
Yes i am . Also it goes in if because empty!=somename. then it makes user_name=empty in database – Furkan Akgün Mar 06 '19 at 15:58

score 0 · Answer 2 · answered Mar 06 '19 at 16:21

0

try this and tell me the output :

  if(isset($_POST['new-username'])){

         $userName=$_POST['new-username'];  }

       else { $userName='default'; }

        if($_SESSION['userName'] !== $userName){
            $sql="UPDATE users SET user_name='$userName' WHERE user_id='$id'"; 
            $query=mysqli_query($conn,$sql);
      header("Location:http://localhost/talktowo
       rldx/Anasayfa/account/index.php#success=update");
      }
       else {
                echo 'something';
            }

answered Mar 06 '19 at 16:21

patron

59
3
10

it does same thing with my code. it works ican change the username but the point is if($_SESSION['userName'] !== $userName) becomes true and i can change it but when there is "elseif" and if dont make any changes in username it still goes this if and skip elseif's – Furkan Akgün Mar 06 '19 at 16:27

How to POST data from value of input if its exist in echo

2 Answers2