With python regex, only those match my pattern but NOT contains '='

Question

I'm new to regex. I'm using regex to match urls, some of the result contains =. I want only those url match my pattern but not contains =.

My pattern is \S+google.com\/\S+-\S+

For example:

MATCH: www.google.com/aa-bb
NOT MATCH: google.com/
NOT MATCH: www.google.com/aa-bb=cc

My current pattern matches 1 and 3, but I want 1 ONLY

With this answer, Regular expression to match a line that doesn't contain a word?, I have tried (?=((?!=).)*)(?=\S+google.com\/\S+-\S+), trying to intersect the result of both match. But it seems regex does not work this way.

Python Regex answers only, please. Thanks!

Please provide the code you have tried so far. You must show you have attempted something. — Fukiyel, Mar 07 '19 at 19:13

Barmar · Answer 1 · 2019-03-07T19:19:06.610

3

Change \S to [^\s=] so it doesn't match spaces or =.

You should also anchor the pattern with ^ and $, so it has to match the entire URL. Otherwise it will match the www.google.com/aa-bb part of www.google.com/aa-bb=cc.

^\S+google\.com\/[^\s=]+-[^\s=]+$

You should also escape literal . in the regexp.

edited Mar 07 '19 at 19:19

answered Mar 07 '19 at 19:17

Barmar

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Also, OP has a mistake- `.` should be escaped with a `\.` – Dillon Davis Mar 07 '19 at 19:19
Thanks! This works as I described! A follow-up question: what if I want to return only what before '='? – shaoooo Mar 07 '19 at 19:24
1

Then get rid of the `$` at the end. It will match as far as it can. – Barmar Mar 07 '19 at 19:28

With python regex, only those match my pattern but NOT contains '='

1 Answers1