How to run a python function every day at specific time

Question

I am trying to run a specific function every day at 18:00, I wrote the folwing code to do that but it did nothing

    today = datetime.today()
    nextDay = (today + timedelta(days=1)).replace(hour=18, minute=0, second=0)
    delta_time = nextDay - today
    secs = delta_time.seconds + 1
    timer = Timer(secs, self.send_officer_report(".send officer report --ad " + today.strftime("%Y/%m/%d"), today.strftime("%Y/%m/%d")))
    timer.start()

I do not want to use cron, I want my script to be OS independent

You should use server side applications like Supervisor – Arash Hatami Mar 10 '19 at 14:24 — Arash Hatami, Mar 10 '19 at 14:24

score 1 · Accepted Answer · answered Mar 16 '19 at 17:25

I found the answer here https://stackoverflow.com/a/16786600/9308420

import schedule
import time

def job():
    print("I'm working...")

schedule.every(10).minutes.do(job)
schedule.every().hour.do(job)
schedule.every().day.at("10:30").do(job)

while 1:
    schedule.run_pending()
    time.sleep(1)

score 0 · Answer 2 · answered Mar 10 '19 at 14:28

0

cron and related applications are the basic way to do this. With your approach, you have to keep the Python interpreter running 24/7, and if it crashes, all your times are off.

answered Mar 10 '19 at 14:28

Joshua Fox

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Thanks, but I do not want to use `cron`, I want my script to be OS independent – Salem Masoud Mar 10 '19 at 19:34
So your question may be a duplicate of this https://stackoverflow.com/questions/373335/how-do-i-get-a-cron-like-scheduler-in-python – Joshua Fox Mar 11 '19 at 11:07

How to run a python function every day at specific time

2 Answers2