Php compare external value to array value if matched

Question

I have this Array ($item):

Array
        (

            [categoria] => Array
                (
                    [0] => Array
                        (
                            [tid] => 6737
                            [name] => Sala VIP
                            [endereco] => 
                            [logo] => 
                            [image] => 
                            [link] => /taxonomy/term/6737
                            [site] => 
                            [color] => 
                            [peso] => 0
                            [icone] => 1
                            [url_emissores] => 
                        )

                )

            [destaque] => 1
        )

And i want to compare if $something is equal to [name] => Sala VIP. How can i do this? Im trying:

if($something == $item[categoria][0].name) {
   #code
}

@Jonnix is it really necessary to use ' ' between words? cant it be just $item[categoria][0][name] ? — Vitor Mascia, Mar 20 '19 at 22:45
@VitorMascia It _can_ work, but I wouldn't recommend it. Without quotes it will try and use constants with those names first, rather than treating them as strings. For the sake of 2 `'`, just use an explicit string. — Jonnix, Mar 20 '19 at 22:51
@VitorMascia - you can use it but you will get a warning. `Use of undefined constant foo assuming 'foo'` or something to that effect. — ArtisticPhoenix, Mar 20 '19 at 22:57

score 0 · Accepted Answer · answered Mar 21 '19 at 00:53

Like mentioned above, you can access an index of an array like ['someIndex']. But if this array is not a constant, you should ensure that that field is actually set or you will get an undefined index error.

Adding an isset() before comparing will prevent such errors:

if(isset($item['categoria'][0]['name']) && $item['categoria'][0]['name'] === $something) {
   #code
}

Hope this helps,

Php compare external value to array value if matched

1 Answers1