RegExpr check if a string contains only % or only whitespaces or a combination

Question

I am trying to create a regExpr te define if a string contains a % or a whitespace or a combination of the 2.

Example:

'%%%%' ---> true
'%    %%%' ---> true
'test%' ---> false

can someone help?

thx a lot

Possible duplicate of [Learning Regular Expressions](https://stackoverflow.com/questions/4736/learning-regular-expressions) — Biffen, Mar 21 '19 at 10:43

score 1 · Accepted Answer · answered Mar 21 '19 at 10:36

1

You can use this regex,

^[% ]+$

Check this JS code demo,

var arr = ['%%%%','%    %%%','test%']

for(s of arr) {
  console.log(s + ' ---> ' +/^[% ]+$/.test(s));
  }

answered Mar 21 '19 at 10:36

1 Answers1