Alternative/faster ways of creating arrays in python 2.7

Question

I have the following code to create an array:

    for i in range(channel_count):
        if not result[i] is None:
            result[i] = array('f', result[i])

    return result

Is there any other faster way to create arrays in python 2.7, so it takes less time to execute the code.

Faster as in "takes less time to type out the code", or "takes less time to execute the code"? — Kevin, Mar 25 '19 at 13:14
@Alderven, there are no arrays in the builtin namespace, but there is a built-in `array` module which defines an `array` type. — Kevin, Mar 25 '19 at 13:15
@alec_djinn, I've never heard of list comprehension before, thank you for the advice, I'll have a look at it! I'm not very experienced in python. — Gооd_Mаn, Mar 25 '19 at 13:18
Either list comprehension or a simple for loop, if you are beginner in python, as my answer below — Devesh Kumar Singh, Mar 25 '19 at 13:18
Caveat emptor on answers involving list comps - while they are more concise, they aren't _much_ faster than the longhand "create an empty list, then append to it in a loop" approach. Related reading: [Are list-comprehensions and functional functions faster than “for loops”?](https://stackoverflow.com/q/22108488/953482) — Kevin, Mar 25 '19 at 13:24

score 0 · Accepted Answer · answered Mar 25 '19 at 13:13

Just define an empty list and use list's append function to append the result to it when the condition holds true

result_arr = []
for i in range(channel_count):
    if not result[i] is None:
        result_arr.append(result[i])
return result

Or list comprehension can be used

result_arr = [r for r in result if not r is None]

score 0 · Answer 2 · answered Mar 25 '19 at 13:18

0

You can do it by comprehensive way by follow.

output_array = [c if not c is None for c in range(channel_count)]

You can find more information on List comrehension from here

answered Mar 25 '19 at 13:18

Devang Padhiyar

2 Answers2