Why does calling my function throw a NameError?

Question

Please help me out with the error in the code

a=input("Enter the number:")
kp(a)

def kp(num):
    for i in range(20):
        print(num*i)

What's the error you are getting? What are you using as input? — FlyingTeller, Mar 26 '19 at 09:26
welcome to stackoverflow! please take the [tour](http://stackoverflow.com/tour), read up on [how to ask a question](https://stackoverflow.com/help/asking) and provide a [minimal, complete and verifiable example](https://stackoverflow.com/help/mcve) that reproduces your problem. — hiro protagonist, Mar 26 '19 at 09:26
@Aran-Fey The wrong order of function call and definition is not the only error in the code, the linked question is therefore not a duplicate — FlyingTeller, Mar 26 '19 at 09:33
@FlyingTeller You mean because `a` is a string? That's perfectly valid. It may not be what the OP wants, but we can't say for sure without a [mcve]. I don't think it's worth reopening the question just to close it for a different reason. — Aran-Fey, Mar 26 '19 at 09:40
sorry messed it up with the string. Now got the output after casting it into an int. Thanks!! @FlyingTeller — Sai, Mar 26 '19 at 09:45

score 0 · Answer 1 · answered Mar 26 '19 at 09:27

0

You should define your function before its calling:

a=input("Enter the number:")

def kp(num):
    for i in range(20):
        print(num*i)
kp(a)

answered Mar 26 '19 at 09:27

vurmux

1 Answers1