How to fill values of variables in json file dynamically in java

Question

I have a json file which looks like

{
  name = VARIABLE1
  age = VARIABLE2
  address
  {
    street = VARIABLE3
    line = VARIABLE4
  }
}

So now i want to read the file in java code and generate the values of VARIABLES and generate the json and post it to a server. Which means i am testing the server with same kind of data but with different values.

How can i do this

I did not understand your question here. Do you want to know how to convert your file from data in json format to java object? — Abhijeet, Apr 05 '19 at 10:36
What you have there is not JSON at all. If it was, you could parse it in maaaany ways. https://stackoverflow.com/questions/2591098/how-to-parse-json-in-java — JB Nizet, Apr 05 '19 at 10:44

score 1 · Accepted Answer · answered Apr 05 '19 at 10:51

What you have provided in the question is not a well formed json. Ignoring that, you can read a well formed json string into a JSONObject, and replace the values as you want :

private static String getData(String name, int age, String street, String line) throws JSONException {
    JSONObject jsonObject = new JSONObject("{  name : VARIABLE1,  age : VARIABLE2,  address : { street : VARIABLE3,    line : VARIABLE4  }}");
    JSONObject address = (JSONObject) jsonObject.get("address");
    jsonObject.put("name", name);
    jsonObject.put("age", age);
    address.put("street", street);
    address.put("line", line);
    return jsonObject.toString();
}

You can call this method as :

getData("Random", 20, "str", "lin");

score 0 · Answer 2 · answered Apr 05 '19 at 12:28

You can use a specific Java object containing all the fields you want (with simple getters and setters) and transform it to Json using whatever library you prefer (ex. Gson, Jackson...). Alternatively, if your Json String is very simple, you can write it by hand and use String.format for replacing the variable values.

How to fill values of variables in json file dynamically in java

2 Answers2