how to reshape the csv file with 2118 row and 22 colums into 4 4 dimension

Question

I want to reshape the CSV row and columns into 4 dimension form that is acceptable for CNN in python.

Rows are 2118 and columns are 22

Use pandas. https://stackoverflow.com/q/42928911/4015990 – user2165 Apr 19 '19 at 09:32 — user2165, Apr 19 '19 at 09:32

score 0 · Answer 1 · answered Apr 19 '19 at 14:30

You first need to figure out the size of each dimension. After that you can use numpy.reshape.

For example we can convert a 2118x22 array into a 2118x22x1x1 array which satisfies the 4 dimensions requirement like:

original_array = np.random.randint(0, 100, (2118, 22))
dim1, dim2, dim3, dim4 = 2118, 22, 1, 1
original_array.reshape((dim1, dim2 , dim3, dim4))

Now your task is figure out the numbers for dim1, dim2, dim3 and dim4.

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